Exam Hack | CIE A2 Maths | P3 | Absolute Value/Inequality Question
Added 2021-03-03 04:23:27 +0000 UTC
Comments
I don't understand when you square an equation and when you don't, cause this qn, |2x+1| + |2x-1| >5, I was trying to square both the sides and work but it won't work, then I realised that the answer is gotten without the square.
Neha Karia
2023-08-29 20:51:08 +0000 UTC√((22a)^2 - 4(15)(-5a^2)) = √((484a^2) + (300a^2)) = √((784a^2)) = 28a
Intuitive
2023-04-29 09:29:37 +0000 UTCHello Mr Jacob. I had an issue with Q8 on the worksheet. I got the quadratic equation x = ( (22a)±√((22a)^2 - 4(15)(-5a^2)) ) / ( 2 (15) ). However I don't understand how you managed to get it simplified to (22a ± 28a) / 30. How did you manage to simplify the whole square root to 28a? Would appreciate it a lot if you could help me out. Thanks.
Siddarth Arora
2023-04-18 18:11:12 +0000 UTChe is the goat!
KAVIN P00931
2022-05-12 08:20:50 +0000 UTCI can’t download the worksheets 😭
Oriana Mas Grimon
2022-04-13 13:06:36 +0000 UTCHi I just wanted to ask where is the content on dividing polynomials since it was a part of the same chapter as absolute values and inequalities
Ayub
2022-04-08 07:36:51 +0000 UTCIt doesn't matter but I would say always use ln(x). As log base e is very useful and used alot in other areas of engineering, science and mathematics. :)
Intuitive
2021-07-26 09:33:04 +0000 UTChey , for the last question , do we take log or lan on both sides to find x. does it matter which one we take?
Niyati Kumaran
2021-07-24 02:34:08 +0000 UTCAll good, ask as many questions as you want. I prioritise people on here so I’ll answer pretty fast usually :)
Intuitive
2021-03-18 06:58:02 +0000 UTCThank you, I get it now
Jessica Zziwa
2021-03-18 04:51:26 +0000 UTCOr in English Minus one 2^x minus another 2^x is minus two 2^x ‘s
Intuitive
2021-03-17 07:57:49 +0000 UTCAwesome glad it’s helping you :)
Intuitive
2021-03-17 07:53:43 +0000 UTC(2^x -1)(2^x-1) = (2^x)(2^x) - (2^x) - (2^x) + 1 Which gives (2^2x) -2(2^x) + 1 Another way to think about it is if you make u = 2^x then the equation is: (u - 1)^2 = u^2 - 2u + 1 Then as u = 2^x this becomes: (2^x)^2 - 2(2^x) + 1
Intuitive
2021-03-17 07:52:08 +0000 UTCI do have one question. In Q2, when you expanded (2^x-1)^2, you got -2(2^x) for (-2^x-2^x), I don't really get how that works
Jessica Zziwa
2021-03-17 02:34:46 +0000 UTCHi. I just joined and the worksheets are helping already. Thank you!
Jessica Zziwa
2021-03-17 02:32:08 +0000 UTCThanks for replying! For you as a teacher Luisana I think this content will be best given to students a couple months before their exams. (As it’s heavily exam focused rather than content focused) Hope everything is going well with your classes :)
Intuitive
2021-03-09 03:21:23 +0000 UTCHi Jacob! I have downloaded the material, but we started classes, and it's been crazy. I'll check it during the weekend for feedback, but you always nail it anyway!
Luisana Guaita
2021-03-09 02:09:30 +0000 UTCWhat do you think? Any questions
Intuitive
2021-03-06 01:56:21 +0000 UTC
